Riddle Me This

**A face** · 18/09/2007, 12:02 PM

You are driving in a car at a constant speed. On your left side is a 'drop off', (The ground is 18-20 inches below the level you are traveling on), and on your right side is a fire engine traveling at the same speed as you. In front of you is a galloping horse, which is the same size as your car and you cannot overtake it. Behind you is a galloping zebra. Both the horse and zebra are also traveling at the same speed as you.

What must you do to safely get out of this highly dangerous situation?

**Lim till i die** · 18/09/2007, 12:17 PM

Maintain your speed??

Alternatively, knock down the horse

**endabob1** · 18/09/2007, 12:27 PM

Get off the merry-go-round your too old and too pi$$ed and there's a queue of kids wanting to use it

**Bluebeard** · 18/09/2007, 1:06 PM

Just take slow deep breaths and eventually the drugs will wear off.

**gilberto_eire** · 18/09/2007, 3:15 PM

signal with your hand for the zebra to overtake you because you are about to break...if he fails when then its his own fault if he rams up the back of you!!

**galwayhoop** · 18/09/2007, 3:26 PM

Originally Posted by endabob1

Get off the merry-go-round your too old and too pi$$ed and there's a queue of kids wanting to use it

**John83** · 18/09/2007, 4:54 PM

Originally Posted by A face

You are driving in a car at a constant speed. On your left side is a 'drop off', (The ground is 18-20 inches below the level you are traveling on), and on your right side is a fire engine traveling at the same speed as you. In front of you is a galloping horse, which is the same size as your car and you cannot overtake it. Behind you is a galloping zebra. Both the horse and zebra are also traveling at the same speed as you.

What must you do to safely get out of this highly dangerous situation?

Ram the horse.

Seriously, A Face, you're not allowed use mobile internet when operating a vehicle. Put the laptop down, and concentrate on the road.

(Can I assume endabob1 got the right answer?)

**pineapple stu** · 18/09/2007, 4:55 PM

Click on New Posts.

Bye!

**Risteard** · 18/09/2007, 5:41 PM

Endabobs answer is clever and surely what Aface was looking for. ?????

However, the fire engine would not be travelling at the same speed as it is either a. rotating slower on a smaller radius or
b. rotating quicker on a larger radius.

**sligoman** · 18/09/2007, 5:42 PM

I've heard this as a joke before and endabob's answer is correct.

**A face** · 18/09/2007, 6:31 PM

Originally Posted by endabob1

Get off the merry-go-round your too old and too pi$$ed and there's a queue of kids wanting to use it

The winner of the cheque book and pen is .... endabob1

Originally Posted by Risteard

However, the fire engine would not be travelling at the same speed as it is either a. rotating slower on a smaller radius or
b. rotating quicker on a larger radius.

Lets not get all technical now shall we

**Risteard** · 18/09/2007, 6:33 PM

Originally Posted by A face

Lets not get all technical now shall we

Technical, pedantic, correct, call it what you want.

**the 12 th man** · 18/09/2007, 8:11 PM

3 men went into a shop to buy a Printer, the manager was out and the assistant sold the men the printer for �30. Shortly afterwards the manager returned and asked where the printer was, "i sold it to 3 men for �30" said the assistant, but it's on special offer today, it's only �25 and gave the assistant �5 to return to the 3 men.
The assistant caught up with them but couldn't divide the �5 between them, so he gave each of the 3 men �1 and kept �2 for himself.
So each of the 3 men paid �10 and had �1 returned = 3 x 9= �27 and the assistant had �2 =�29 in total, where did the other �1 go!

**gilberto_eire** · 18/09/2007, 8:28 PM

Originally Posted by the 12 th man

3 men went into a shop to buy a Printer, the manager was out and the assistant sold the men the printer for �30. Shortly afterwards the manager returned and asked where the printer was, "i sold it to 3 men for �30" said the assistant, but it's on special offer today, it's only �25 and gave the assistant �5 to return to the 3 men.
The assistant caught up with them but couldn't divide the �5 between them, so he gave each of the 3 men �1 and kept �2 for himself.
So each of the 3 men paid �10 and had �1 returned = 3 x 9= �27 and the assistant had �2 =�29 in total, where did the other �1 go!

ya i remember a differant version of that.... it came to my head the last day but i couldnt remember how it went.... i dont get that...its weird!!

**John83** · 18/09/2007, 8:28 PM

Originally Posted by Risteard

Technical, pedantic, correct, call it what you want.

There was no mention of any curvature of the road, so you are making an unsupported assumption.

/pedant

**John83** · 18/09/2007, 8:30 PM

Originally Posted by the 12 th man

3 men went into a shop to buy a Printer, the manager was out and the assistant sold the men the printer for �30. Shortly afterwards the manager returned and asked where the printer was, "i sold it to 3 men for �30" said the assistant, but it's on special offer today, it's only �25 and gave the assistant �5 to return to the 3 men.
The assistant caught up with them but couldn't divide the �5 between them, so he gave each of the 3 men �1 and kept �2 for himself.
So each of the 3 men paid �10 and had �1 returned = 3 x 9= �27 and the assistant had �2 =�29 in total, where did the other �1 go!

You don't add the �2, you take it away to get �25, the price of the printer.

**holidaysong** · 19/09/2007, 12:01 AM

Originally Posted by Risteard

However, the fire engine would not be travelling at the same speed as it is either a. rotating slower on a smaller radius or
b. rotating quicker on a larger radius.

If the fire engine is opposite to the car on the merry go round then there is no reason to assume that it is on a smaller or larger radius. The OP didn't specify which direction the fire engine was travelling in so it is obviously possible that it is travelling at the same speed.